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Beliebt Algebra >

(x^2+2^2)(x-1)^3(x^2-9)>= 0

Lösung

(x^{2} + 2^{2}) \cdot (x - 1)^{3} \cdot (x^{2} - 9) \geq 0

Lösung

- 3 \leq x \leq 1 or x \geq 3

+1

Intervall-Notation

[- 3, 1] \cup [3, \infty)

Schritte zur Lösung

(x^{2} + 2^{2}) (x - 1)^{3} (x^{2} - 9) \geq 0

Faktorisiere

(x^{2} + 2^{2}) (x - 1)^{3} (x^{2} - 9) : (x - 1)^{3} (x + 3) (x - 3) (x^{2} + 4)

(x - 1)^{3} (x + 3) (x - 3) (x^{2} + 4) \geq 0

Identifiziere die Intervalle

- 3 \leq x \leq 1 or x \geq 3

Graph

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