(2x-1)/(x+1)<0

Lösung

\frac{2 x - 1}{x + 1} < 0

- 1 < x < \frac{1}{2}

Intervall-Notation

(- 1, \frac{1}{2})

Dezimale

- 1 < x < 0.5

Schritte zur Lösung

\frac{2 x - 1}{x + 1} < 0

Identifiziere die Intervalle

- 1 < x < \frac{1}{2}

\frac{( 3 n ^{2} )}{( n ^{2} - 1 )} < 0

\frac{3}{( x + 1 )} \geq 0

p^{2} - 16 p > 0

(x + 2)^{2} > (x + 3) (x - 3)

(x - 2)^{4} \geq 0