(x-1)(4-x)(x-5)^2<0

Lösung

(x - 1) (4 - x) (x - 5)^{2} < 0

x < 1 or 4 < x < 5 or x > 5

Intervall-Notation

(- \infty, 1) \cup (4, 5) \cup (5, \infty)

Schritte zur Lösung

(x - 1) (4 - x) (x - 5)^{2} < 0

Identifiziere die Intervalle

x < 1 or 4 < x < 5 or x > 5

4 x^{2} - 7 x - 15 > 0

\frac{3}{( x + 1 )} > 0

2 x - x^{2} \geq 1 x

(x^{2} - x)^{2} + 3 (x^{2} - x) + 2 \geq 0

x^{2} + 20 x + 100 < 0