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Beliebt Algebra >

((x^3+1))/((7x^2-1))<= 0

Lösung

\frac{( x ^{3} + 1 )}{( 7 x ^{2} - 1 )} \leq 0

Lösung

x \leq - 1 or - \frac{1}{7} < x < \frac{1}{7}

+2

Intervall-Notation

(- \infty, - 1] \cup (- \frac{1}{7}, \frac{1}{7})

Dezimale

x \leq - 1 or - 0.37796 \dots < x < 0.37796 \dots

Schritte zur Lösung

\frac{x ^{3} + 1}{7 x ^{2} - 1} \leq 0

Faktor

\frac{x ^{3} + 1}{7 x ^{2} - 1} : \frac{( x + 1 ) ( x ^{2} - x + 1 )}{( 7 x + 1 ) ( 7 x - 1 )}

\frac{( x + 1 ) ( x ^{2} - x + 1 )}{( 7 x + 1 ) ( 7 x - 1 )} \leq 0

Identifiziere die Intervalle

x \leq - 1 or - \frac{1}{7} < x < \frac{1}{7}

Graph

Beliebte Beispiele

\frac{1}{( x ^{2} )} \leq 4

((3x-x^4))/(((x+4)^2))>= 0

\frac{( 3 x - x ^{4} )}{( ( x + 4 ) ^{2} )} \geq 0

25 x^{2} - 40 x + 16 < 0

((x-2))/((x+3))<2

\frac{( x - 2 )}{( x + 3 )} < 2

-(x-1)(x-3)>= 0

- (x - 1) (x - 3) \geq 0