((13x-4))/((5x+7))>0

Lösung

\frac{( 13 x - 4 )}{( 5 x + 7 )} > 0

x < - \frac{7}{5} or x > \frac{4}{13}

Intervall-Notation

(- \infty, - \frac{7}{5}) \cup (\frac{4}{13}, \infty)

Dezimale

x < - 1.4 or x > 0.30769 \dots

Schritte zur Lösung

\frac{13 x - 4}{5 x + 7} > 0

Identifiziere die Intervalle

x < - \frac{7}{5} or x > \frac{4}{13}

(x - 7) (x - 2) > 0

x^{3} > - 2 x

s^{3} - 8 > 4

\frac{( x + 3 )}{( x + 16 )} \geq \frac{3}{( x - 4 )}

x^{3} + 8 x^{2} < 0