|2x+3|> 1/2

Lösung

∣ 2 x + 3 ∣ > \frac{1}{2}

x < - \frac{7}{4} or x > - \frac{5}{4}

Intervall-Notation

(- \infty, - \frac{7}{4}) \cup (- \frac{5}{4}, \infty)

Dezimale

x < - 1.75 or x > - 1.25

Schritte zur Lösung

∣ 2 x + 3 ∣ > \frac{1}{2}

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

2 x + 3 < - \frac{1}{2} or 2 x + 3 > \frac{1}{2}

2 x + 3 < - \frac{1}{2} or 2 x + 3 > \frac{1}{2}

x < - \frac{7}{4} or x > - \frac{5}{4}

\frac{2 x - 3}{x - 1} > 3

\frac{( x + 1 )}{( x - 1 )} < 1

∣ x - 2 ∣ \leq ∣ x - 4 ∣

∣ 2 x - 1 ∣ > x + 1

∣ 2 x + 1 ∣ > x + 5