1/4+5/12+((-1))/(13)<x< 17/5+2/10+1/2

Lösung

\frac{1}{4} + \frac{5}{12} + \frac{( - 1 )}{13} < x < \frac{17}{5} + \frac{2}{10} + \frac{1}{2}

\frac{23}{39} < x < \frac{41}{10}

Intervall-Notation

(\frac{23}{39}, \frac{41}{10})

Dezimale

0.58974 \dots < x < 4.1

Schritte zur Lösung

\frac{1}{4} + \frac{5}{12} + \frac{( - 1 )}{13} < x < \frac{17}{5} + \frac{2}{10} + \frac{1}{2}

\frac{1}{4} + \frac{5}{12} + \frac{( - 1 )}{13} = \frac{23}{39}

\frac{17}{5} + \frac{2}{10} + \frac{1}{2} = \frac{41}{10}

\frac{23}{39} < x < \frac{41}{10}

0 < \frac{6}{x} < \frac{6}{7}

\frac{- 12}{17} < x < \frac{- 8}{17}

- 1 < 3 + 4 x < 23

- 1 < n < 0

4 < x^{2} < 121