lcm b^2+d^2+a^2,2x+5+x-5+2x

解答

lcm

b^{2} + d^{2} + a^{2}, 2 x + 5 + x - 5 + 2 x

5 (b^{2} + d^{2} + a^{2}) x

求解步骤

找到

b^{2} + d^{2} + a^{2}, 2 x + 5 + x - 5 + 2 x

的最小公倍数

分解

2 x + 5 + x - 5 + 2 x : 5 x

将最高次数乘以每个因数:

5 \cdot (b^{2} + d^{2} + a^{2}) \cdot x

l c m 16 - x^{4}, 16 + 8 x^{2} + x^{4}, 16 - 8 x^{2} + x^{4}

l c m 3 m^{2}, - 4 m^{2}, - 7 m^{2}, 2 m^{2}

l c m x^{2} - 3 x - 4, x^{2} - 8 x + 15

l c m 2 x^{2} - 9 x, 5 - 3 x

l c m \frac{4}{x}, \frac{( 3 x + 4 )}{7}