lcm j^{411}*(-12)+(-3),-15

解答

lcm

j^{411} \cdot (- 12) + (- 3), - 15

45 (4^{\frac{2}{3}} j^{274} - 34 j^{137} + 1) (34 j^{137} + 1)

求解步骤

找到

j^{411} \cdot (- 12) + (- 3), - 15

的最小公倍数

分解

j^{411} (- 12) + (- 3) : - 3 (34 j^{137} + 1) (4^{\frac{2}{3}} j^{274} - 34 j^{137} + 1)

将最高次数乘以每个因数:

- (- 15) \cdot 3 \cdot (4^{\frac{2}{3}} j^{274} - 34 j^{137} + 1) \cdot (34 j^{137} + 1)

化简

45 (4^{\frac{2}{3}} j^{274} - 34 j^{137} + 1) (34 j^{137} + 1)

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l c m 36 \frac{g}{c} \cdot m^{3}, 360 \frac{g}{c} \cdot m^{3}, 36 \frac{g}{c} \cdot m^{3}

l c m (0), \frac{r}{\frac{12}{3}}

l c m a, \frac{14}{13} + \frac{15}{22} + \frac{9}{13} + \frac{7}{22} - 2

l c m 7 x - 5 y + 8 z, 2 x + 6 y - 3 z, - 9 x - y - 5 z