因式分解 20r^4s-20r^3s+5r^2s

解答

因式分解

20 r^{4} s - 20 r^{3} s + 5 r^{2} s

5 r^{2} s (2 r - 1)^{2}

求解步骤

20 r^{4} s - 20 r^{3} s + 5 r^{2} s

因式分解出通项

5 r^{2} s : 5 r^{2} s (4 r^{2} - 4 r + 1)

= 5 r^{2} s (4 r^{2} - 4 r + 1)

因式分解

4 r^{2} - 4 r + 1 : (2 r - 1) (2 r - 1)

= 5 r^{2} s (2 r - 1) (2 r - 1)

使用指数法则:

aa = a^{2}

(2 r - 1) (2 r - 1) = (2 r - 1)^{2}

= 5 r^{2} s (2 r - 1)^{2}

s im pl i f y (1 - 7 n) \cdot 5

f a c t or a^{5} - 4 a b^{4}

s im pl i f y 2 \frac{1}{3} + (- 1 \frac{2}{3})

s im pl i f y 8 (5 k + 7) - 10 (6 k - 7)

s im pl i f y \frac{x}{x + 3}