3x^2-5x-2>= 0

Lösung

3 x^{2} - 5 x - 2 \geq 0

x \leq - \frac{1}{3} or x \geq 2

Intervall-Notation

(- \infty, - \frac{1}{3}] \cup [2, \infty)

Dezimale

x \leq - 0.33333 \dots or x \geq 2

Schritte zur Lösung

3 x^{2} - 5 x - 2 \geq 0

Faktorisiere

3 x^{2} - 5 x - 2 : (3 x + 1) (x - 2)

(3 x + 1) (x - 2) \geq 0

Identifiziere die Intervalle

x \leq - \frac{1}{3} or x \geq 2

3 x^{2} - 5 x - 2 = 0

x^{2} = 38

∣ 3 x - 1 ∣ = 13

467 = - 0.5 x^{2} + 36 x - 145

x^{2} + 6 x - 8 = 0