化简 (2x+20-6x^2)-(4-7x^2+12x)

解答

化简

(2 x + 20 - 6 x^{2}) - (4 - 7 x^{2} + 12 x)

x^{2} - 10 x + 16

求解步骤

(2 x + 20 - 6 x^{2}) - (4 - 7 x^{2} + 12 x)

使用法则:

(a) = a

(2 x + 20 - 6 x^{2}) = 2 x + 20 - 6 x^{2}

= 2 x + 20 - 6 x^{2} - (4 - 7 x^{2} + 12 x)

使用分配律:

- (a - b) = - a + b

- (4 - 7 x^{2} + 12 x) = - 4 + 7 x^{2} - 12 x

= 2 x + 20 - 6 x^{2} - 4 + 7 x^{2} - 12 x

对同类项分组

= - 6 x^{2} + 7 x^{2} + 2 x - 12 x + 20 - 4

1 \frac{5}{12}

s im pl i f y \frac{4 a ^{2}}{27 a}

s im pl i f y \frac{x ^{2} + 4 x - 5}{x ^{2} - 2 x + 1}

f a c t or 3 x^{4} - 16 x^{2}

s im pl i f y - 3 y - 5 x^{3} + 6 + 2 - 4 y + 5 y + 6 x^{3}