What are the solutions to the equation y^2+9=-10y ?

The solutions to the equation y^2+9=-10y are y=-1,y=-9

Find the zeros of y^2+9=-10y

The zeros of y^2+9=-10y are y=-1,y=-9

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y^{2} + 9 = - 10 y

y = - 1, y = - 9

Solution steps

y^{2} + 9 = - 10 y

Move

10 y

to the left side

y^{2} + 9 + 10 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} + 10 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 9 = 8

y_{1, 2} = \frac{- 10 \pm 8}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 10 + 8}{2 \cdot 1}, y_{2} = \frac{- 10 - 8}{2 \cdot 1}

y = \frac{- 10 + 8}{2 \cdot 1} : - 1

y = \frac{- 10 - 8}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

y = - 1, y = - 9

\frac{x}{4} + \frac{2}{5} = 5

\frac{7}{3} (2 x - 1) = \frac{1}{5} x + \frac{2}{5} (4 - 3 x)

(x - 5) (x - 2) (x + 1) > 0

x y + 6 y - 8 x - 48

2 x^{2} + x \geq 1

What are the solutions to the equation y^2+9=-10y ?
The solutions to the equation y^2+9=-10y are y=-1,y=-9
Find the zeros of y^2+9=-10y
The zeros of y^2+9=-10y are y=-1,y=-9