What is (3x^2+4x-3)-(4x^2-3x+2) ?

The solution to (3x^2+4x-3)-(4x^2-3x+2) is -x^2+7x-5

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simplify (3x^2+4x-3)-(4x^2-3x+2)

simplify

(3 x^{2} + 4 x - 3) - (4 x^{2} - 3 x + 2)

- x^{2} + 7 x - 5

Solution steps

(3 x^{2} + 4 x - 3) - (4 x^{2} - 3 x + 2)

Apply rule:

(a) = a

(3 x^{2} + 4 x - 3) = 3 x^{2} + 4 x - 3

= 3 x^{2} + 4 x - 3 - (4 x^{2} - 3 x + 2)

Apply the distributive law:

- (a - b) = - a + b

- (4 x^{2} - 3 x + 2) = - 4 x^{2} + 3 x - 2

= 3 x^{2} + 4 x - 3 - 4 x^{2} + 3 x - 2

Group like terms

= 3 x^{2} - 4 x^{2} + 4 x + 3 x - 3 - 2

Add similar elements:

3 x^{2} - 4 x^{2} = - x^{2}

= - x^{2} + 4 x + 3 x - 3 - 2

Add similar elements:

4 x + 3 x = 7 x

= - x^{2} + 7 x - 3 - 2

Subtract the numbers:

- 3 - 2 = - 5

= - x^{2} + 7 x - 5

36 x^{3} - 42 y^{4} + 24 z

\frac{1}{5} (- \frac{2}{3})

2 \cdot 1

4 x^{2} - 8 x + 32

(2 t + 1) (t - 4)

What is (3x^2+4x-3)-(4x^2-3x+2) ?
The solution to (3x^2+4x-3)-(4x^2-3x+2) is -x^2+7x-5