What is 3x^2-x^2+1-x[x-(2x-1)]+2 ?

The solution to 3x^2-x^2+1-x[x-(2x-1)]+2 is 3x^2-x+3

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simplify 3x^2-x^2+1-x[x-(2x-1)]+2

simplify

3 x^{2} - x^{2} + 1 - x [x - (2 x - 1)] + 2

3 x^{2} - x + 3

Solution steps

3 x^{2} - x^{2} + 1 - x (x - (2 x - 1)) + 2

Group like terms

= 3 x^{2} - x^{2} - x (x - (2 x - 1)) + 1 + 2

Add similar elements:

3 x^{2} - x^{2} = 2 x^{2}

= 2 x^{2} - x (x - (2 x - 1)) + 1 + 2

Add the numbers:

1 + 2 = 3

= 2 x^{2} - x (x - (2 x - 1)) + 3

Simplify

x - (2 x - 1) : - x + 1

= 2 x^{2} - x (- x + 1) + 3

Expand

- x (- x + 1) : x^{2} - x

= 2 x^{2} + x^{2} - x + 3

Add similar elements:

2 x^{2} + x^{2} = 3 x^{2}

= 3 x^{2} - x + 3

57 \div 19

(- 5) (- 7)

(- 5) (- 6)

16 x^{4} - 8 x^{2} + 1

60 \frac{4}{45}

What is 3x^2-x^2+1-x[x-(2x-1)]+2 ?
The solution to 3x^2-x^2+1-x[x-(2x-1)]+2 is 3x^2-x+3