faktorisieren sin^6(x)+cos^6(x)

Lösung

faktorisieren

sin^{6} (x) + cos^{6} (x)

(sin^{2} (x) + cos^{2} (x)) (sin^{4} (x) - sin^{2} (x) cos^{2} (x) + cos^{4} (x))

Schritte zur Lösung

sin^{6} (x) + cos^{6} (x)

Schreibe

sin^{6} (x) + cos^{6} (x)

um:

(sin^{2} (x))^{3} + (cos^{2} (x))^{3}

= (sin^{2} (x))^{3} + (cos^{2} (x))^{3}

Wende Formel zur Summe von dritten Potenzen an:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(sin^{2} (x))^{3} + (cos^{2} (x))^{3} = (sin^{2} (x) + cos^{2} (x)) (sin^{4} (x) - sin^{2} (x) cos^{2} (x) + cos^{4} (x))

= (sin^{2} (x) + cos^{2} (x)) (sin^{4} (x) - sin^{2} (x) cos^{2} (x) + cos^{4} (x))

f a c t or (x - 5) (x - (3 + 22))

f (x) = (tan (x))^{2}

f (x) = [x]

f a c t or [(x + 1) - y]^{2}

f a c t or [(x - 3) + y]^{2}