因式分解 ab+ac+b^2+bc

解答

因式分解

ab + a c + b^{2} + b c

(b + c) (a + b)

求解步骤

ab + a c + b^{2} + b c

因式分解出通项

a

= a (b + c) + b^{2} + b c

使用指数法则:

a^{b + c} = a^{b} a^{c}

b^{2} = bb

= a (b + c) + bb + b c

因式分解出通项

b

= a (b + c) + b (b + c)

因式分解出通项

(b + c)

= (b + c) (a + b)

f a c t or [(x - 6) + y]^{2}

f a c t or e (x)

f a c t or 4 X + 2 Y - 6 + 5 X + 7 Y - 1

f a c t or - 6 (x t^{4})

f a c t or - 3 A e^{- 3 x} + 2 B e^{2 x} + 4 C e^{4 x}