因式分解 (e^8-1)/(40)

解答

因式分解

\frac{e ^{8} - 1}{40}

\frac{( e ^{4} + 1 ) ( e ^{2} + 1 ) ( e + 1 ) ( e - 1 )}{40}

求解步骤

\frac{e ^{8} - 1}{40}

分解

e^{8} - 1 : (e^{4} + 1) (e^{2} + 1) (e + 1) (e - 1)

= \frac{( e ^{4} + 1 ) ( e ^{2} + 1 ) ( e + 1 ) ( e - 1 )}{40}

f a c t or cos (180 - 2 a)

f a c t or x y - x z + 3 y - 3 z

f a c t or (x - 5) + (4 x^{2})

f a c t or 9 b^{2 x} - \frac{1}{4}

s im pl i f y e^{2 + 2 i}