因式分解 2^2+9b-b^2

解答

因式分解

2^{2} + 9 b - b^{2}

- (b - \frac{9 + 97}{2}) (b - \frac{9 - 97}{2})

求解步骤

2^{2} + 9 b - b^{2}

因式分解出通项

- 1

= - (b^{2} - 9 b - 2^{2})

分解

b^{2} - 9 b - 2^{2} : (b - \frac{9 + 97}{2}) (b - \frac{9 - 97}{2})

= - (b - \frac{9 + 97}{2}) (b - \frac{9 - 97}{2})

f a c t or \frac{x ^{3} + 8}{x - 2}

f a c t or 3 ab + 12 a d - 8 c d - 2 b c

f a c t or t^{2} + 14 t + 21

f a c t or a + ab + a b^{'} c

s im pl i f y K^{3} + 2 F