因式分解 z^6+6z^4+12z^2+8

解答

因式分解

z^{6} + 6 z^{4} + 12 z^{2} + 8

(z^{2} + 2)^{3}

求解步骤

z^{6} + 6 z^{4} + 12 z^{2} + 8

令

u = z^{2}

= u^{3} + 6 u^{2} + 12 u + 8

分解

u^{3} + 6 u^{2} + 12 u + 8 : (u + 2) (u + 2) (u + 2)

= (u + 2) (u + 2) (u + 2)

u = z^{2}

代回

= (z^{2} + 2) (z^{2} + 2) (z^{2} + 2)

整理后得

= (z^{2} + 2)^{3}

f a c t or l {e^{2 t} cosh (t)}

f (x) = 25 (sec (5 x))^{2}

f a c t or (a + b)^{2} - (a - b^{2})

s im pl i f y - 6 (x)^{2} + y^{3} - 8

f a c t or \infty^{3} - \infty