因式分解 1+ab+m(a+b)+m(ab+1)+a+b

解答

因式分解

1 + ab + m (a + b) + m (ab + 1) + a + b

(1 + a + b + ab) (m + 1)

求解步骤

1 + ab + m (a + b) + m (ab + 1) + a + b

因式分解出通项

m

= m (a + b + 1 + ab) + a + b + 1 + ab

改写为

= (1 + a + b + ab) m + 1 \cdot (1 + a + b + ab)

因式分解出通项

(1 + a + b + ab)

= (1 + a + b + ab) (m + 1)

f a c t or (2 n + 4 \frac{k}{n})^{2}

f a c t or 2 (x - 1)^{2} + 3 (x - 1) + 1

f a c t or \frac{( ab - a )}{b ^{2} - b}

f a c t or R - [5]

f a c t or x^{8} - 4 x^{4} y^{4} + 3 y^{8}