faktorisieren (x-1)^4+5(x-1)^2+9

Lösung

faktorisieren

(x - 1)^{4} + 5 (x - 1)^{2} + 9

x^{4} - 4 x^{3} + 11 x^{2} - 14 x + 15

Schritte zur Lösung

(x - 1)^{4} + 5 (x - 1)^{2} + 9

(x - 1)^{4} : x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1

= x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 + 5 (x - 1)^{2} + 9

(x - 1)^{2} : x^{2} - 2 x + 1

= x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 + 5 (x^{2} - 2 x + 1) + 9

Multipliziere aus

5 (x^{2} - 2 x + 1) : 5 x^{2} - 10 x + 5

= x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 + 5 x^{2} - 10 x + 5 + 9

Vereinfache

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 + 5 x^{2} - 10 x + 5 + 9 : x^{4} - 4 x^{3} + 11 x^{2} - 14 x + 15

= x^{4} - 4 x^{3} + 11 x^{2} - 14 x + 15

f a c t or m^{7} + a^{7} x^{7}

f a c t or (x + 3)^{3} - 8

f a c t or A u (N O^{3}) 3

f a c t or 0.064 x^{27} - 1.331 b^{15}

\frac{d}{d t} ((x) (t cos (t)))