faktorisieren 1-e^{12}

Lösung

faktorisieren

1 - e^{12}

- (e^{2} + 1) (e + 1) (e - 1) (e^{8} + e^{4} + 1)

Schritte zur Lösung

1 - e^{12}

Klammere gleiche Terme aus

- 1

= - (e^{12} - 1)

Faktorisiere

e^{12} - 1 : (e^{2} + 1) (e + 1) (e - 1) (e^{8} + e^{4} + 1)

= - (e^{2} + 1) (e + 1) (e - 1) (e^{8} + e^{4} + 1)

f a c t or \frac{( x - 1 )}{x}

f a c t or 20 e^{2} + 47 ey + 24 e^{2}

s im pl i f y x^{(2 n)} cos (x)

f a c t or (x + 3) (x + 2) (x + 1) + 1

f a c t or 1 - e^{10}