因式分解 2(x+1)^3-3(x+1)^2-6

解答

因式分解

2 (x + 1)^{3} - 3 (x + 1)^{2} - 6

2 x^{3} + 3 x^{2} - 7

求解步骤

2 (x + 1)^{3} - 3 (x + 1)^{2} - 6

(x + 1)^{3} : x^{3} + 3 x^{2} + 3 x + 1

= 2 (x^{3} + 3 x^{2} + 3 x + 1) - 3 (x + 1)^{2} - 6

(x + 1)^{2} : x^{2} + 2 x + 1

= 2 (x^{3} + 3 x^{2} + 3 x + 1) - 3 (x^{2} + 2 x + 1) - 6

乘开

2 (x^{3} + 3 x^{2} + 3 x + 1) : 2 x^{3} + 6 x^{2} + 6 x + 2

= 2 x^{3} + 6 x^{2} + 6 x + 2 - 3 (x^{2} + 2 x + 1) - 6

乘开

- 3 (x^{2} + 2 x + 1) : - 3 x^{2} - 6 x - 3

= 2 x^{3} + 6 x^{2} + 6 x + 2 - 3 x^{2} - 6 x - 3 - 6

化简

2 x^{3} + 6 x^{2} + 6 x + 2 - 3 x^{2} - 6 x - 3 - 6 : 2 x^{3} + 3 x^{2} - 7

= 2 x^{3} + 3 x^{2} - 7

f a c t or ab - 2 b + a y - 2 y

f a c t or 9 - 3 x

f a c t or 2 n^{2} - 0.7 n + 0.05

f a c t or (64 x y)^{(\frac{1}{3})}

s im pl i f y [60]