What is factor 2x^{-4}-7x^{-3}+x^{-2} ?

The solution to factor 2x^{-4}-7x^{-3}+x^{-2} is (2-7x+x^2)/(x^4)

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factor 2x^{-4}-7x^{-3}+x^{-2}

factor

2 x^{- 4} - 7 x^{- 3} + x^{- 2}

\frac{2 - 7 x + x ^{2}}{x ^{4}}

Solution steps

2 x^{- 4} - 7 x^{- 3} + x^{- 2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{- 3} = x^{- 4} x, x^{- 2} = x^{- 4} x^{2}

= 2 x^{- 4} - 7 x^{- 4} x + x^{- 4} x^{2}

Factor out common term

x^{- 4}

= x^{- 4} (2 - 7 x + x^{2})

Refine

= \frac{x ^{2} - 7 x + 2}{x ^{4}}

(2.3) m^{4}

6 x^{2} - 13 + 6

x^{2} - \frac{7}{2} x + 3

\frac{32}{s ^{2} + 12 s + 32}

2 a + (b + 3)

What is factor 2x^{-4}-7x^{-3}+x^{-2} ?
The solution to factor 2x^{-4}-7x^{-3}+x^{-2} is (2-7x+x^2)/(x^4)