展开 2(ln(x)+1)

解答

展开

2 (ln (x) + 1)

2 ln (x) + 2

求解步骤

2 (ln (x) + 1)

使用分配律:

a (b + c) = ab + a c

a = 2, b = ln (x), c = 1

= 2 ln (x) + 2 \cdot 1

数字相乘:

2 \cdot 1 = 2

= 2 ln (x) + 2

e x p an d \frac{x + 1 - a}{( x + 1 ) ( x - 1 )}

e x p an d (- e^{- x}) (2 - sin (2 x))

e x p an d 2 x (y + 1) d x

e x p an d (200 - e^{2}) \cdot 100

e x p an d e^{2 x} + (1 - 2 x) e^{x} + x^{2} - 1