erweitern (2x-1)^2ln(3x+4)

Lösung

erweitern

(2 x - 1)^{2} ln (3 x + 4)

4 x^{2} ln (3 x + 4) - 4 x ln (3 x + 4) + ln (3 x + 4)

Schritte zur Lösung

(2 x - 1)^{2} ln (3 x + 4)

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= ln (3 x + 4) (4 x^{2} - 4 x + 1)

= ln (3 x + 4) (4 x^{2} - 4 x + 1)

Setze Klammern

= ln (3 x + 4) \cdot 4 x^{2} + ln (3 x + 4) (- 4 x) + ln (3 x + 4) \cdot 1

Wende Minus-Plus Regeln an

+ (- a) = - a

= 4 x^{2} ln (3 x + 4) - 4 x ln (3 x + 4) + 1 \cdot ln (3 x + 4)

Multipliziere:

1 \cdot ln (3 x + 4) = ln (3 x + 4)

= 4 x^{2} ln (3 x + 4) - 4 x ln (3 x + 4) + ln (3 x + 4)

e x p an d sin (t (t - \frac{π}{6}))

e x p an d (x - 2) e^{3}

e x p an d \frac{( 2 x + 1 ) n ^{2}}{( n + 1 ) ^{2}}

e x p an d (x^{2} + 6 x + 6) e^{x}

e x p an d (x - 2) e^{2}