展开 a+be^{a(t-m)}

解答

展开

a + b e^{a (t - m)}

a + e^{a t - ma} b

求解步骤

a + b e^{a (t - m)}

e^{a (t - m)} = e^{a t - ma}

= a + e^{a t - ma} b

e x p an d (2 - e)^{3}

e x p an d \frac{d x}{( 1 - x ) ( 2 - x )}

e x p an d e^{2 t} (3 t + 6)

e x p an d (y + x y) d x

e x p an d Q (5, - 4)