展开 pi(2x+pi)^2

解答

展开

π (2 x + π)^{2}

4 π x^{2} + 4 π^{2} x + π^{3}

求解步骤

π (2 x + π)^{2}

(2 x + π)^{2} = 4 x^{2} + 4 π x + π^{2}

= π (4 x^{2} + 4 π x + π^{2})

打开括号

= π 4 x^{2} + π 4 π x + π π^{2}

= 4 π x^{2} + 4 ππ x + π^{2} π

化简

4 π x^{2} + 4 ππ x + π^{2} π : 4 π x^{2} + 4 π^{2} x + π^{3}

= 4 π x^{2} + 4 π^{2} x + π^{3}

e x p an d \frac{8}{( 3 x - 4 ) ^{2}}

e x p an d \frac{x + 4}{x ( x + 12 )}

\frac{d}{d t} ((x) (2 t + 2 t^{3}))

e x p an d A (4, - 10) B (- 6, - 8)

e x p an d \frac{6}{( 2 x + 7 ) ^{4}}