展开 6(x+Δx)^2-8(x+Δx)

解答

展开

6 (x + Δ x)^{2} - 8 (x + Δ x)

6 x^{2} + 12Δ x^{2} + 6 Δ^{2} x^{2} - 8 x - 8Δ x

求解步骤

6 (x + Δ x)^{2} - 8 (x + Δ x)

乘开

- 8 (x + Δ x) : - 8 x - 8Δ x

= 6 (x + Δ x)^{2} - 8 x - 8Δ x

化简

6 (x + Δ x)^{2} - 8 x - 8Δ x : 6 x^{2} + 12Δ x^{2} + 6 Δ^{2} x^{2} - 8 x - 8Δ x

= 6 x^{2} + 12Δ x^{2} + 6 Δ^{2} x^{2} - 8 x - 8Δ x

e x p an d (\frac{( 3 y - 3 )}{2})^{2}

e x p an d - \frac{269 e - 178}{192 ( e - 2 )}

e x p an d (m^{2} - n - 8) - (3 m^{2} + 6 n - 2,)

e x p an d (3 - e^{- t}) (4 + e^{- 2 t})

e x p an d \frac{( n + 1 ) ! ( n + 2 )}{( n - 1 )}