展开 x(12xy^2+3y+4=0)

解答

展开

x (12 x y^{2} + 3 y + 4 = 0)

12 x^{2} y^{2} + 3 x y + 4 x = 0

求解步骤

x (12 x y^{2} + 3 y + 4 = 0)

= x (12 x y^{2} + 3 y + 4 \cdot 0 =)

打开括号

x \cdot 12 x y^{2} + x \cdot 3 y + x \cdot 4 = 0

12 xx y^{2} + 3 x y + 4 x = 0

乘开

12 xx y^{2} + 3 x y + 4 x : 12 x^{2} y^{2} + 3 x y + 4 x

12 x^{2} y^{2} + 3 x y + 4 x = 0

e x p an d Q (1, - 3)

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e x p an d A (- 1, 2) B (2, - 1)

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