展开 d(1+i)/(2-i)

解答

展开

d \frac{1 + i}{2 - i}

\frac{d}{5} + \frac{3 i d}{5}

求解步骤

d \frac{1 + i}{2 - i}

\frac{1 + i}{2 - i} = \frac{1 + 3 i}{5}

= \frac{1 + 3 i}{5} d

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 1 + 3 i ) d}{5}

乘开

(1 + 3 i) d : d + 3 i d

= \frac{d + 3 i d}{5}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{d + 3 i d}{5} = \frac{d}{5} + \frac{3 i d}{5}

= \frac{d}{5} + \frac{3 i d}{5}

e x p an d \frac{5 - x}{x ( x - 2 )}

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e x p an d (x^{2} + 3 x - 2) (ln (x))