展开 ((x+1)(2y+1))/8

解答

展开

\frac{( x + 1 ) ( 2 y + 1 )}{8}

\frac{x y}{4} + \frac{x}{8} + \frac{y}{4} + \frac{1}{8}

求解步骤

\frac{( x + 1 ) ( 2 y + 1 )}{8}

乘开

(x + 1) (2 y + 1) : 2 x y + x + 2 y + 1

= \frac{2 x y + x + 2 y + 1}{8}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x y + x + 2 y + 1}{8} = \frac{2 x y}{8} + \frac{x}{8} + \frac{2 y}{8} + \frac{1}{8}

= \frac{2 x y}{8} + \frac{x}{8} + \frac{2 y}{8} + \frac{1}{8}

消掉

\frac{2 x y}{8} : \frac{x y}{4}

= \frac{x y}{4} + \frac{x}{8} + \frac{2 y}{8} + \frac{1}{8}

消掉

\frac{2 y}{8} : \frac{y}{4}

= \frac{x y}{4} + \frac{x}{8} + \frac{y}{4} + \frac{1}{8}

e x p an d \frac{x + 3}{( x - 6 ) ^{3}}

e x p an d (2 x^{3} + 2) (2 x^{3} - 5)^{'}

e x p an d \frac{4 x + 14}{( x + 5 ) ( x - 1 )}

e x p an d (a + b c) + (d e + f) (a + b)

e x p an d x - 3 (x^{2} (x^{3} + 8))