展開する (y^1=2,-x^2)(y_{2}=-x)

解

展開する

(y^{1} = 2, - x^{2}) (y_{2} = - x)

y = x^{3}

解答ステップ

(y^{1} = 2, - x^{2}) (y_{2} = - x)

= (2 =, y^{1} - x^{2}) (= y_{2} - x)

FOIL メソッドを適用する:

(a + b) (c + d) = a c + a d + b c + b d

a = y^{1} = 2,, b = - x^{2}, c = y_{2} =, d = - x

y^{1} = 2, y_{2} = y^{1} = 2, (- x) + (- x^{2}) y_{2} = (- x^{2}) (- x)

マイナス・プラスの規則を適用する

+ (- a) = - a, (- a) (- b) = ab

y^{1} = 2, y_{2} = - y^{1} = 2, x - x^{2} y_{2} = x^{2} x

簡素化

y^{1} = 2, y_{2} = - y^{1} = 2, x - x^{2} y_{2} = x^{2} x : y = x^{3}

y = x^{3}