展开 ((3-2x^2)^2)/2

解答

展开

\frac{( 3 - 2 x ^{2} ) ^{2}}{2}

2 x^{4} - 6 x^{2} + \frac{9}{2}

求解步骤

\frac{( 3 - 2 x ^{2} ) ^{2}}{2}

(3 - 2 x^{2})^{2} = 9 - 12 x^{2} + 4 x^{4}

= \frac{9 - 12 x ^{2} + 4 x ^{4}}{2}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 12 x ^{2} + 4 x ^{4}}{2} = \frac{9}{2} - \frac{12 x ^{2}}{2} + \frac{4 x ^{4}}{2}

= \frac{9}{2} - \frac{12 x ^{2}}{2} + \frac{4 x ^{4}}{2}

数字相除:

\frac{12}{2} = 6

= \frac{9}{2} - 6 x^{2} + \frac{4 x ^{4}}{2}

数字相除:

\frac{4}{2} = 2

= \frac{9}{2} - 6 x^{2} + 2 x^{4}

改写为标准形式

= 2 x^{4} - 6 x^{2} + \frac{9}{2}

e x p an d \frac{2 R}{( R ^{2} + 9 ) ^{2}}

e x p an d \frac{3 x + 2}{x ( x ^{2} - 9 )}

e x p an d ln (y^{2} + z^{2})

e x p an d \frac{( y ^{6} - 4 ) ^{2}}{16 y ^{6}}

e x p an d \frac{x ^{3} ( 3 x + 8 )}{12}