展开 P(1,-3,2)Q(2,1,-1)

解答

展开

P (1, - 3, 2) Q (2, 1, - 1)

1 \cdot PQ, 2, 1, - 1 \cdot PQ, 1 - 3 PQ, 2 \cdot 2, 1, 3, 2 \cdot 1

求解步骤

P (1, - 3, 2) Q (2, 1, - 1)

= (1, - 3 \cdot 2,) (2 \cdot 1,, - 1) PQ

乘开

(1, - 3, 2) (2, 1, - 1) : 1, 2, 1, - 1, 1 - 3, 2 \cdot 2, 1, 3, 2 \cdot 1

= PQ (1, 2, 1, - 1, 1 - 3, 2 \cdot 2, 1, 3, 2 \cdot 1)

乘开

PQ (1, 2, 1, - 1, 1 - 3, 2 \cdot 2, 1, 3, 2 \cdot 1) : 1 \cdot PQ, 2, 1, - 1 \cdot PQ, 1 - 3 PQ, 2 \cdot 2, 1, 3, 2 \cdot 1

= 1 \cdot PQ, 2, 1, - 1 \cdot PQ, 1 - 3 PQ, 2 \cdot 2, 1, 3, 2 \cdot 1

e x p an d \frac{d}{d x} ((x + 1) e^{- x}) + x

e x p an d \frac{2 x ^{2} + 2 x - 4}{( 2 x + 1 ) ^{2}}

e x p an d \frac{( x + 6 ) ^{2}}{4}

e x p an d \frac{4 y - 3 ( x - 1 ) ^{2}}{z + 9}

e x p an d - 2.2 (- 12 - 5 y = - 27)