展开 possible 1/3 (3j+6)

解答

展开

p oss ib l e \frac{1}{3} (3 j + 6)

i (2 e lp o s^{2} b + e l j p o s^{2} b)

求解步骤

p oss ib l e \frac{1}{3} (3 j + 6)

= i e \frac{1}{3} lp oss b (3 j + 6)

使用分配律:

a (b + c) = ab + a c

a = p oss ib l e \frac{1}{3}, b = 3 j, c = 6

= p oss ib l e \frac{1}{3} \cdot 3 j + p oss ib l e \frac{1}{3} \cdot 6

= 3 i e \frac{1}{3} l j p oss b + 6 i e \frac{1}{3} lp oss b

化简

3 i e \frac{1}{3} l j p oss b + 6 i e \frac{1}{3} lp oss b : i (2 e lp o s^{2} b + e l j p o s^{2} b)

= i (2 e lp o s^{2} b + e l j p o s^{2} b)

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