展开 (-y'(t)+1)^2

解答

展开

(- y^{'} (t) + 1)^{2}

(y' (t))^{2} - 2 y' (t) + 1

求解步骤

(- y^{'} (t) + 1)^{2}

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = - y^{'} (t), b = 1

= (- y^{^{'}} (t))^{2} + 2 (- y^{^{'}} (t)) \cdot 1 + 1^{2}

化简

(- y^{'} (t))^{2} + 2 (- y^{'} (t)) \cdot 1 + 1^{2} : (y^{'} (t))^{2} - 2 y^{'} (t) + 1

= (y^{'} (t))^{2} - 2 y^{'} (t) + 1

e x p an d 4 f^{'} (- 1) (3 x + 4)

e x p an d \frac{e ^{2 x} ( 2 x + 1 )}{( x + 1 ) ^{2}}

e x p an d \frac{( 2 + x ) ( - 4 + x )}{- 9 - x}

\frac{d}{d v} ((s) (4 t - 1))

e x p an d \frac{x ^{2} ( 49 - x ^{2} ) 3}{2 d x}