erweitern (n(n+1)(2n+a))/6

Lösung

erweitern

\frac{n ( n + 1 ) ( 2 n + a )}{6}

\frac{n ^{3}}{3} + \frac{a n ^{2}}{6} + \frac{n ^{2}}{3} + \frac{an}{6}

Schritte zur Lösung

\frac{n ( n + 1 ) ( 2 n + a )}{6}

Multipliziere aus

n (n + 1) (2 n + a) : 2 n^{3} + a n^{2} + 2 n^{2} + an

= \frac{2 n ^{3} + a n ^{2} + 2 n ^{2} + an}{6}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 n ^{3} + a n ^{2} + 2 n ^{2} + an}{6} = \frac{2 n ^{3}}{6} + \frac{a n ^{2}}{6} + \frac{2 n ^{2}}{6} + \frac{an}{6}

= \frac{2 n ^{3}}{6} + \frac{a n ^{2}}{6} + \frac{2 n ^{2}}{6} + \frac{an}{6}

Streiche

\frac{2 n ^{3}}{6} : \frac{n ^{3}}{3}

= \frac{n ^{3}}{3} + \frac{a n ^{2}}{6} + \frac{2 n ^{2}}{6} + \frac{an}{6}

Streiche

\frac{2 n ^{2}}{6} : \frac{n ^{2}}{3}

= \frac{n ^{3}}{3} + \frac{a n ^{2}}{6} + \frac{n ^{2}}{3} + \frac{an}{6}

e x p an d e^{(a + jb) t}

e x p an d (4 x - y = 5,) (5 x + 2 y = 3)

e x p an d u (2, 5) w (3, - 2)

e x p an d \frac{( 136 - 13 y ) \cdot y}{6}

e x p an d \frac{a ^{2} + 5 a + 25}{a ( a + 2 )}