erweitern ((3x-2)(2x-1))/6

Lösung

erweitern

\frac{( 3 x - 2 ) ( 2 x - 1 )}{6}

x^{2} - \frac{7 x}{6} + \frac{1}{3}

Schritte zur Lösung

\frac{( 3 x - 2 ) ( 2 x - 1 )}{6}

Multipliziere aus

(3 x - 2) (2 x - 1) : 6 x^{2} - 7 x + 2

= \frac{6 x ^{2} - 7 x + 2}{6}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} - 7 x + 2}{6} = \frac{6 x ^{2}}{6} - \frac{7 x}{6} + \frac{2}{6}

= \frac{6 x ^{2}}{6} - \frac{7 x}{6} + \frac{2}{6}

Teile die Zahlen:

\frac{6}{6} = 1

= x^{2} - \frac{7 x}{6} + \frac{2}{6}

Streiche

\frac{2}{6} : \frac{1}{3}

= x^{2} - \frac{7 x}{6} + \frac{1}{3}

e x p an d \frac{- x ^{2} + 2 x}{( x - 1 ) ^{2}}

e x p an d \frac{( 4 x ^{4} - 1 ) ^{2}}{4 x ^{2}}

e x p an d (\frac{1}{3}) 5

e x p an d 5 (1 - 2 ln (x))

e x p an d (a^{2} + 3 a + 2)^{6}