展开 ((t+Δt)-1)^2

解答

展开

((t + Δ t) - 1)^{2}

2Δ t^{2} + Δ^{2} t^{2} - 2Δ t + t^{2} - 2 t + 1

求解步骤

((t + Δ t) - 1)^{2}

去除括号:

(a) = a

= (t + Δ t - 1)^{2}

(t + Δ t - 1)^{2} = (t + Δ t - 1) (t + Δ t - 1)

= (t + Δ t - 1) (t + Δ t - 1)

乘开

(t + Δ t - 1) (t + Δ t - 1) : 2Δ t^{2} + Δ^{2} t^{2} - 2Δ t + t^{2} - 2 t + 1

= 2Δ t^{2} + Δ^{2} t^{2} - 2Δ t + t^{2} - 2 t + 1

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