展开 (2-0.1t^2)dt

解答

展开

(2 - 0.1 t^{2}) d t

2 d t - 0.1 t^{2} d t

求解步骤

(2 - 0.1 t^{2}) d t

使用分配律:

a (b - c) = ab - a c

a = d t, b = 2, c = 0.1 t^{2}

= d t \cdot 2 - d t \cdot 0.1 t^{2}

= 2 d t - 0.1 t^{2} d t

e x p an d y (0.8 x + 0.2 y = 0)

e x p an d \frac{( x + a ) ^{2} - a}{a}

e x p an d \frac{( - x + 15 ) ( - x + 10 )}{2}

e x p an d \frac{( a ^{2 n} - 1 ) ^{2}}{a ^{2 n}}

e x p an d \frac{1}{3 ^{x} ( 3 ^{2 - x} + 1 )}