展开 (pi(sin(2θ)+1))/3

解答

展开

\frac{π ( sin ( 2 θ ) + 1 )}{3}

\frac{π sin ( 2 θ )}{3} + \frac{π}{3}

求解步骤

\frac{π ( sin ( 2 θ ) + 1 )}{3}

乘开

π (sin (2 θ) + 1) : π sin (2 θ) + π

= \frac{π sin ( 2 θ ) + π}{3}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π sin ( 2 θ ) + π}{3} = \frac{π sin ( 2 θ )}{3} + \frac{π}{3}

= \frac{π sin ( 2 θ )}{3} + \frac{π}{3}

e x p an d \frac{6 x}{2 x}

e x p an d - \frac{3 t ^{2}}{( t ^{3} + 1 ) ^{2}}

e x p an d \frac{( 2 k + 3 ) ( k + 2 ) ( k + 1 )}{6}

e x p an d e x p an (3 z - 2) (z^{2} - 3 z - 4)

e x p an d \frac{4}{( x + 5 ) ^{2}}