展开 sec(a)nte(90-θ)-sin(o)(90-θ)

解答

展开

sec (a) n t e (90 - θ) - sin (o) (90 - θ)

90 e n t sec (a) - e n tθ sec (a) - 90 sin (o) + θ sin (o)

求解步骤

sec (a) n t e (90 - θ) - sin (o) (90 - θ)

= e n t sec (a) (90 - θ) - sin (o) (90 - θ)

乘开

sec (a) n t e (90 - θ) : 90 e n t sec (a) - e n tθ sec (a)

= 90 e n t sec (a) - e n tθ sec (a) - sin (o) (90 - θ)

乘开

- sin (o) (90 - θ) : - 90 sin (o) + θ sin (o)

= 90 e n t sec (a) - e n tθ sec (a) - 90 sin (o) + θ sin (o)

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e x p an d d x (x + \frac{1}{x})