展开 (e^x)*(e^x+xe^x)

解答

展开

(e^{x}) \cdot (e^{x} + x e^{x})

e^{2 x} + e^{2 x} x

求解步骤

(e^{x}) (e^{x} + x e^{x})

= (e^{x}) (e^{x} + e^{x} x)

使用分配律:

a (b + c) = ab + a c

a = (e^{x}), b = e^{x}, c = x e^{x}

= (e^{x}) e^{x} + (e^{x}) x e^{x}

= e^{x} (e^{x}) + e^{x} x (e^{x})

化简

e^{x} (e^{x}) + e^{x} x (e^{x}) : e^{2 x} + e^{2 x} x

= e^{2 x} + e^{2 x} x

e x p an d (b + f i) (a - e i) + (d + hi) (c - g i)

\frac{d}{d x} ((x) 3 x (x + 4)^{2})

e x p an d \frac{2 ( s + 2 )}{s ^{2} + 4 s + 3}

e x p an d - \frac{4}{( x + 1 ) ^{2}}

e x p an d 2 x e^{x} + e^{x} (x^{2} - 1)