erweitern ((3c+4)(3c-2))/(144)

Lösung

erweitern

\frac{( 3 c + 4 ) ( 3 c - 2 )}{144}

\frac{c ^{2}}{16} + \frac{c}{24} - \frac{1}{18}

Schritte zur Lösung

\frac{( 3 c + 4 ) ( 3 c - 2 )}{144}

Multipliziere aus

(3 c + 4) (3 c - 2) : 9 c^{2} + 6 c - 8

= \frac{9 c ^{2} + 6 c - 8}{144}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 c ^{2} + 6 c - 8}{144} = \frac{9 c ^{2}}{144} + \frac{6 c}{144} - \frac{8}{144}

= \frac{9 c ^{2}}{144} + \frac{6 c}{144} - \frac{8}{144}

Streiche

\frac{9 c ^{2}}{144} : \frac{c ^{2}}{16}

= \frac{c ^{2}}{16} + \frac{6 c}{144} - \frac{8}{144}

Streiche

\frac{6 c}{144} : \frac{c}{24}

= \frac{c ^{2}}{16} + \frac{c}{24} - \frac{8}{144}

Streiche

\frac{8}{144} : \frac{1}{18}

= \frac{c ^{2}}{16} + \frac{c}{24} - \frac{1}{18}

e x p an d (ln (x) + 1) \cdot (2 ln (x) - 1)

e x p an d (d x - 4) 3

e x p an d (- 6, - 10) y (- 2, - 2)

e x p an d 3 (x - 1 = 2 x + 9)

e x p an d (a - 2) (a + 3)^{''}