展开 (x+Δx)^2-4(x+Δx)+5

解答

展开

(x + Δ x)^{2} - 4 (x + Δ x) + 5

x^{2} + 2Δ x^{2} + Δ^{2} x^{2} - 4 x - 4Δ x + 5

求解步骤

(x + Δ x)^{2} - 4 (x + Δ x) + 5

乘开

- 4 (x + Δ x) : - 4 x - 4Δ x

= (x + Δ x)^{2} - 4 x - 4Δ x + 5

(x + Δ x)^{2} : x^{2} + 2Δ x^{2} + Δ^{2} x^{2}

= x^{2} + 2Δ x^{2} + Δ^{2} x^{2} - 4 x - 4Δ x + 5

e x p an d (- 3, - 5, - 1) x (- 4, 5, 7)

e x p an d \frac{1}{( x - 1 ) ( x + 2 ) ( 2 x + 1 )}

e x p an d 2 - 6 (5 + 2 [3 + 5 (8 - 7 \cdot, 8)])

e x p an d \frac{( - 4 - i ) ^{7}}{( 2 - 3 i ) ^{5}}

e x p an d \frac{1}{( 1 - n ) ^{2}}