展开 2*(3x-10)

解答

展开

2 \cdot (3 x - 1 0^{\circ})

6 x - 2 \cdot 1 0^{\circ}

求解步骤

2 (3 x - 1 0^{\circ})

使用分配律:

a (b - c) = ab - a c

a = 2, b = 3 x, c = 1 0^{\circ}

= 2 \cdot 3 x - 2 \cdot 1 0^{\circ}

数字相乘:

2 \cdot 3 = 6

= 6 x - 2 \cdot 1 0^{\circ}

e x p an d (ab + c d) (e f g)

e x p an d \frac{x ( x + y )}{y ( x - y )}

e x p an d \frac{x ( 4 x + 7 )}{4 x - 7}

e x p an d \frac{15}{10}

e x p an d (2 b)^{2} - (- b)^{2}