What is expand (1-e^{-jkpi})^2 ?

The solution to expand (1-e^{-jkpi})^2 is 1-2e^{-pijk}+e^{-2pijk}

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expand (1-e^{-jkpi})^2

expand

(1 - e^{- jkπ})^{2}

1 - 2 e^{- πjk} + e^{- 2 πjk}

Solution steps

(1 - e^{- jkπ})^{2}

= (1 - e^{- πjk})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 1, b = e^{- jkπ}

= 1^{2} - 2 \cdot 1 \cdot e^{- jkπ} + (e^{- jkπ})^{2}

Simplify

1^{2} - 2 \cdot 1 \cdot e^{- jkπ} + (e^{- jkπ})^{2} : 1 - 2 e^{- πjk} + e^{- 2 πjk}

= 1 - 2 e^{- πjk} + e^{- 2 πjk}

\frac{1}{s ( s ^{2} + 4 s + 4 )}

\frac{d}{d t} ((x) (x (2) - 2))

\frac{d y}{x ( 2 x - 1 ) ^{2} e ^{x} + 2 y}

\frac{d}{d y} ((m) (2 x - 1))

4 π (x + 2)^{2}

What is expand (1-e^{-jkpi})^2 ?
The solution to expand (1-e^{-jkpi})^2 is 1-2e^{-pijk}+e^{-2pijk}