展开 (V(2pi-φ))/((2pi-1))

解答

展开

\frac{V ( 2 π - φ )}{( 2 π - 1 )}

\frac{2 πV - V φ}{2 π - 1}

求解步骤

\frac{V ( 2 π - φ )}{2 π - 1}

乘开

V (2 π - φ) : 2 πV - V φ

= \frac{2 πV - V φ}{2 π - 1}

e x p an d s q u a re x (2 x + 1)

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e x p an d \frac{5 ( 2 x + 3 )}{2 ( 4 x - 5 )}

e x p an d (\frac{x + 1}{x})^{2}

e x p an d \frac{s - 10}{s ( s - 3 ) ( s + 3 )}